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(B) In a standard pack of $52$ cards,there are $4$ suits: Hearts,Diamonds,Clubs,and Spades.Hearts and Diamonds are red suits,while Clubs and Spades ar

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$\frac{1}{26}$

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(B) In a standard pack of $52$ cards,there are $4$ suits: Hearts,Diamonds,Clubs,and Spades.Hearts and Diamonds are red suits,while Clubs and Spades are black suits.Each suit contains exactly one ace.Therefore,the number of aces of red suits is $2$ (one ace of Hearts and one ace of Diamonds).The total number of possible outcomes is $52$.The number of favorable outcomes is $2$.Probability $= \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{2}{52} = \frac{1}{26}$.

$A$ card is drawn at random from a well-shuffled pack of $52$ cards. The probability that the card drawn is an ace of a red suit is ...........

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