A cell when dipped in 0.5 M sucrose solution | vedclass

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(D) Sucrose is a non-electrolyte,so $0.5 \ M$ sucrose solution has an osmotic concentration of $0.5 \ Osm$. Since it has no effect on the cell,the cel

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Will get plasmolysed

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(D) Sucrose is a non-electrolyte,so $0.5 \ M$ sucrose solution has an osmotic concentration of $0.5 \ Osm$. Since it has no effect on the cell,the cell's internal osmotic concentration is also $0.5 \ Osm$ (isotonic condition).$NaCl$ is an electrolyte that dissociates into $Na^+$ and $Cl^-$ ions. Therefore,a $0.5 \ M$ $NaCl$ solution has an osmotic concentration of approximately $1.0 \ Osm$ $(0.5 	imes 2)$.Because the $NaCl$ solution $(1.0 \ Osm)$ is hypertonic compared to the cell's internal environment $(0.5 \ Osm)$,water will move out of the cell via osmosis.As water leaves the cell,the protoplast shrinks away from the cell wall,a process known as plasmolysis.

$A$ cell when dipped in $0.5 \ M$ sucrose solution has no effect,but when the same cell is dipped in $0.5 \ M$ $NaCl$ solution,the cell will:

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