A certain buffer solution contains equal conc | vedclass

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(A) Given that the concentration of $X^{-}$ and $HX$ are equal,$[X^{-}] = [HX]$.For the conjugate acid-base pair,$K_a 	imes K_b = K_w = 10^{-14}$.$K_

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$4$

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(A) Given that the concentration of $X^{-}$ and $HX$ are equal,$[X^{-}] = [HX]$.For the conjugate acid-base pair,$K_a 	imes K_b = K_w = 10^{-14}$.$K_a = \frac{K_w}{K_b} = \frac{10^{-14}}{10^{-10}} = 10^{-4}$.$pK_a = -\log(K_a) = -\log(10^{-4}) = 4$.Using the Henderson-Hasselbalch equation: $pH = pK_a + \log \frac{[X^{-}]}{[HX]}$.Since $[X^{-}] = [HX]$,$\log \frac{[X^{-}]}{[HX]} = \log(1) = 0$.Therefore,$pH = pK_a = 4$.

$A$ certain buffer solution contains equal concentration of $X^{-}$ and $HX$. The $K_b$ for $X^{-}$ is $10^{-10}$. The $pH$ of the buffer is

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