A certain radioactive nuclide of mass number | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In radioactive decay involving the emission of an electron (beta decay,$\beta^-$),a neutron in the nucleus is converted into a proton and an elect

Vedclass · Accepted Answer

$m_y = m_x$

Vedclass · Answer

(D) In radioactive decay involving the emission of an electron (beta decay,$\beta^-$),a neutron in the nucleus is converted into a proton and an electron (and an antineutrino). The process is represented as: $n ightarrow p + e^- + \bar{
u}_e$. The mass number $A$ is the total number of protons and neutrons. Since one neutron is lost and one proton is gained,the total number of nucleons remains constant. The emission of $\gamma$ radiation involves the release of energy from an excited nucleus and does not change the mass number or atomic number. Therefore,the mass number of the daughter nucleus $(m_y)$ is equal to the mass number of the parent nucleus $(m_x)$. Thus,$m_y = m_x$.

$A$ certain radioactive nuclide of mass number $m_x$ disintegrates,with the emission of an electron and $\gamma$ radiation only,to give a second nuclide of mass number $m_y$. Which one of the following equations correctly relates $m_x$ and $m_y$?

Similar Questions

In the nuclear decay sequence given below:
$_Z{X^A} \to {}_{Z + 1}{Y^A} \to {}_{Z - 1}{K^{A - 4}} \to {}_{Z - 1}{K^{A - 4}}$
the particles emitted in the sequence are:

In which radioactive disintegration does a neutron dissociate into a proton and an electron?

In the disintegration series
$_{92}^{238}U \xrightarrow{\alpha} X \xrightarrow{\beta} _{Z}^{A}Y$
The values of $Z$ and $A$ respectively will be:

$\beta$-rays emitted by a radioactive material are

When a radioactive isotope ${}_{88}^{228}Ra$ decays in series by the emission of $3$ alpha particles and $1$ beta particle,the isotope finally formed is

Vedclass Test Series

Exam Paper Generator

Online Exam Module