A charge q is located at the centre of a cube | vedclass

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(A) According to Gauss's Law,the total electric flux $\phi_{total}$ through a closed surface is given by $\phi_{total} = \frac{q}{\varepsilon_0}$.Sinc

Vedclass · Accepted Answer

$\frac{4\pi q}{6(4\pi \varepsilon_0)}$

Vedclass · Answer

(A) According to Gauss's Law,the total electric flux $\phi_{total}$ through a closed surface is given by $\phi_{total} = \frac{q}{\varepsilon_0}$.Since the charge $q$ is placed at the centre of a cube,the flux is distributed equally through all $6$ faces of the cube.Therefore,the electric flux through any one face is $\phi_{face} = \frac{\phi_{total}}{6} = \frac{q}{6\varepsilon_0}$.To match the given options,we multiply the numerator and denominator by $4\pi$:$\phi_{face} = \frac{q 	imes 4\pi}{6 	imes \varepsilon_0 	imes 4\pi} = \frac{4\pi q}{6(4\pi \varepsilon_0)}$.

$A$ charge $q$ is located at the centre of a cube. The electric flux through any face is

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