A charged particle (charge q) is moving in a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic moment $\mu$ of a current loop is given by $\mu = I A$. Here,the current $I$ produced by the revolving charge $q$ is $I = \frac{q}{T}

Vedclass · Accepted Answer

$\frac{qvR}{2}$

Vedclass · Answer

(D) The magnetic moment $\mu$ of a current loop is given by $\mu = I A$. Here,the current $I$ produced by the revolving charge $q$ is $I = \frac{q}{T}$,where $T$ is the time period of revolution. The time period $T$ for a particle moving in a circle of radius $R$ with speed $v$ is $T = \frac{2 \pi R}{v}$. Substituting $T$ into the expression for $I$,we get $I = \frac{q}{2 \pi R / v} = \frac{qv}{2 \pi R}$. The area $A$ of the circular path is $A = \pi R^2$. Therefore,the magnetic moment is $\mu = I A = \left( \frac{qv}{2 \pi R} \right) (\pi R^2) = \frac{qvR}{2}$.

$A$ charged particle (charge $q$) is moving in a circle of radius $R$ with uniform speed $v.$ The associated magnetic moment $\mu$ is given by

Similar Questions

$A$ current-carrying loop consists of $3$ identical quarter circles of radius $R$,lying in the positive quadrants of the $xy$,$yz$,and $zx$ planes with their centers at the origin,joined together. Find the direction and magnitude of the magnetic field $\vec{B}$ at the origin.

The radius of a circular loop is $r$ and a current $i$ is flowing in it. The equivalent magnetic moment will be

$A$ current-carrying small loop behaves like a small magnet. If $A$ is its area and $M$ is its magnetic moment,the current in the loop will be

$A$ wire of length $L$ metre carrying a current of $I$ ampere is bent in the form of a circle. Its magnetic moment is:

$A$ charged particle (charge $= q$; mass $= m$) is rotating in a circle of radius $R$ with uniform speed $V$. The ratio of its magnetic moment $(\mu)$ to the angular momentum $(L)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module