A charged particle is moving in a circular or | vedclass

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Question

(B) Given:Speed $v = 3 	imes 10^6 \, m/s$Magnetic field $B = 2 	imes 10^{-4} \, T$Radius $R = 6 \, cm = 6 	imes 10^{-2} \, m$For a charged particle

Vedclass · Accepted Answer

$2.5 	imes 10^{11} \, C/kg$

Vedclass · Answer

(B) Given:Speed $v = 3 	imes 10^6 \, m/s$Magnetic field $B = 2 	imes 10^{-4} \, T$Radius $R = 6 \, cm = 6 	imes 10^{-2} \, m$For a charged particle moving in a circular path in a magnetic field,the magnetic Lorentz force provides the necessary centripetal force:$Bqv = \frac{mv^2}{R}$Rearranging the formula to find the charge to mass ratio $(q/m)$:$\frac{q}{m} = \frac{v}{BR}$Substituting the given values:$\frac{q}{m} = \frac{3 	imes 10^6}{(2 	imes 10^{-4}) 	imes (6 	imes 10^{-2})}$$\frac{q}{m} = \frac{3 	imes 10^6}{12 	imes 10^{-6}}$$\frac{q}{m} = 0.25 	imes 10^{12} \, C/kg = 2.5 	imes 10^{11} \, C/kg$Thus,the correct option is $B$.

$A$ charged particle is moving in a circular orbit of radius $6 \, cm$ with a uniform speed of $3 \times 10^6 \, m/s$ under the action of a uniform magnetic field $2 \times 10^{-4} \, Wb/m^2$ which is at right angles to the plane of the orbit. The charge to mass ratio of the particle is

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