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(A) The Lorentz force on a charged particle is given by $\vec{F} = q(\vec{E} + \vec{v} 	imes \vec{B})$.Since the particle is released from rest,its i

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straight line

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(A) The Lorentz force on a charged particle is given by $\vec{F} = q(\vec{E} + \vec{v} 	imes \vec{B})$.Since the particle is released from rest,its initial velocity $\vec{v} = 0$.Therefore,the initial magnetic force $\vec{F}_m = q(\vec{v} 	imes \vec{B}) = 0$.The electric force $\vec{F}_e = q\vec{E}$ acts on the particle,causing it to accelerate in the direction of the electric field.As the particle gains velocity $\vec{v}$,it remains parallel to the magnetic field $\vec{B}$ because the electric field and magnetic field are parallel.Since $\vec{v} \parallel \vec{B}$,the cross product $\vec{v} 	imes \vec{B} = 0$ at all times.Thus,the magnetic force remains zero throughout the motion.The particle only experiences the electric force,which causes it to move in a straight line along the direction of the electric field.

$A$ charged particle is released from rest in a region of uniform electric and magnetic fields which are parallel to each other. The particle will move on a

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