A charged particle moves through a magnetic f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When a charged particle moves in a magnetic field with velocity $\vec{v}$ perpendicular to the magnetic field $\vec{B}$,the magnetic force acting

Vedclass · Accepted Answer

speed of the particle remains unchanged

Vedclass · Answer

(B) When a charged particle moves in a magnetic field with velocity $\vec{v}$ perpendicular to the magnetic field $\vec{B}$,the magnetic force acting on it is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Since the force $\vec{F}$ is always perpendicular to the velocity $\vec{v}$,the work done by the magnetic force on the particle is zero $(W = \vec{F} \cdot \vec{d} = 0)$.According to the work-energy theorem,the change in kinetic energy is equal to the work done. Since work done is zero,the kinetic energy remains constant.As kinetic energy $K = \frac{1}{2}mv^2$,a constant kinetic energy implies that the speed $(v)$ of the particle remains unchanged.However,because the force acts perpendicular to the velocity,it changes the direction of motion,causing the particle to move in a circular path. Thus,velocity and acceleration change continuously.

$A$ charged particle moves through a magnetic field in a direction perpendicular to it. Then the

Similar Questions

An electrically charged particle enters a uniform magnetic field in a direction perpendicular to the field with a velocity $v$. Then, it travels:

$A$ uniform magnetic field acts at right angles to the direction of motion of electrons. As a result,the electron moves in a circular path of radius $2\, cm$. If the speed of the electrons is doubled,then the radius of the circular path will be.....$cm$.

$A$ strong magnetic field is applied on a stationary electron. Then,the electron

$A$ charged particle of charge $q$ and mass $m$ is accelerated through a potential difference of $V$ volts. It enters a region of orthogonal magnetic field $B$. The radius of its circular path will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module