$A$ charged particle oscillates about its mean equilibrium position with a frequency of $10^9 \; Hz$. What is the frequency of the electromagnetic waves produced by the oscillator?

If $10 \%$ of the power of a $(100 \pi) \ W$ light bulb is converted to visible radiation,then the average intensity of visible radiation at a distance of $10 \ m$ is (in $W \ m^{-2}$)

$A$ plane electromagnetic wave propagates along the $+x$ direction in free space. The components of the electric field,$\overrightarrow{E}$ and magnetic field,$\overrightarrow{B}$ vectors associated with the wave in a Cartesian frame are:

The electric field part of an electromagnetic wave in a medium is represented by $E_x=0, E_y=2.5 \frac{N}{C} \cos \left[ (2\pi \times 10^6 \frac{rad}{s})t - (\pi \times 10^{-2} \frac{rad}{m})x \right]$,and $E_z=0$. The wave is

The electric field for an electromagnetic wave in free space is $E = i 30 \cos (k z - 5 \times 10^8 t)$,where the magnitude of $E$ is in $V/m$. The magnitude of the wave vector $k$ is (velocity of electromagnetic wave in free space $= 3 \times 10^8 \ m/s$).

$A$ plane electromagnetic wave is incident on a surface. If this wave transfers momentum $P$ and energy $U$ to the surface,then: