$A$ circuit contains an ammeter,a battery of $30\,V$ and a resistance of $40.8\,\Omega$ all connected in series. If the ammeter has a coil of resistance $480\,\Omega$ and a shunt of $20\,\Omega$,the reading in the ammeter will be .................. $A$.

  • A
    $1$
  • B
    $0.25$
  • C
    $0.5$
  • D
    $2$

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Similar Questions

$A$ galvanometer of resistance $100 \Omega$ requires $10 \mu A$ current for full-scale deflection. If a shunt resistance of $1 \Omega$ is connected in parallel to convert it into an ammeter, what is the minimum current required to obtain full-scale deflection (in $\text{ mA}$)?

Which of the following statements is incorrect?

$A$ galvanometer coil has a resistance of $10 \Omega$ and the meter shows full scale deflection for a current of $2 \text{ mA}$. What resistance needs to be connected to convert the meter into a voltmeter of range $0$ to $18 \text{ V}$ (in $\Omega$)?

$A$ moving coil galvanometer has $50$ turns and each turn has an area $2 \times 10^{-4} \ m^2$. The magnetic field produced by the magnet inside the galvanometer is $0.02 \ T$. The torsional constant of the suspension wire is $10^{-4} \ N \ m \ rad^{-1}$. When a current flows through the galvanometer,a full-scale deflection occurs if the coil rotates by $0.2 \ rad$. The resistance of the coil of the galvanometer is $50 \ \Omega$. This galvanometer is to be converted into an ammeter capable of measuring current in the range $0-1.0 \ A$. For this purpose,a shunt resistance is to be added in parallel to the galvanometer. The value of this shunt resistance,in ohms,is:

The resistance of a galvanometer is $50\, \Omega$ and the maximum current which can be passed through it is $0.002\, A$. What resistance must be connected to it in order to convert it into an ammeter of range $0 - 0.5\, A$?

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