$A$ circuit has a section $AB$ as shown in the figure. If the potential difference between points $A$ and $B$ is $V$ volts,then the potential difference across $C_1$ is

In the arrangement of the capacitors as shown in the figure,each capacitor is of $6 \mu F$. Find the equivalent capacitance between points $A$ and $B$. (in $\mu F$)

The minimum number of capacitors of $2\,\mu F$ capacitance each required to obtain a resultant capacitance of $5\,\mu F$ is

Three capacitors $C_1$,$C_2$,and $C_3$ are connected in parallel,and their equivalent capacitance is $12$ units. Given $C_1 \cdot C_2 \cdot C_3 = 48$ units. When $C_1$ and $C_2$ are connected in parallel,their equivalent capacitance is $6$ units. Find the individual capacitances $C_1, C_2, C_3$.

$A$ $5 \mu F$ capacitor is connected in series with a $10 \mu F$ capacitor. When a $300 \ V$ potential difference is applied across this combination, the total energy stored in the capacitors is (in $J$)

What is the equivalent capacitance between $A$ and $B$ in the given circuit (in $\mu F$)?