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(B) The magnetic flux $\phi$ through the loop is given by $\phi = B \cdot A$,where $B$ is the magnetic field and $A$ is the area of the loop.When the

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Anti-clockwise current is induced

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(B) The magnetic flux $\phi$ through the loop is given by $\phi = B \cdot A$,where $B$ is the magnetic field and $A$ is the area of the loop.When the loop is stretched outwards,its area $A$ increases.Since the magnetic field $B$ is directed into the plane,the magnetic flux through the loop increases.According to Lenz's Law,the induced current will flow in a direction that opposes this increase in magnetic flux.To oppose the increase in inward magnetic flux,the induced magnetic field must be directed outwards.By the right-hand thumb rule,a current flowing in a clockwise direction produces a magnetic field directed into the plane,while a counter-clockwise current produces a field directed outwards.Wait,let us re-evaluate: If the flux is directed into the plane and is increasing,the induced current must create a magnetic field directed out of the plane to oppose the change.Therefore,the induced current must be anti-clockwise.Correction: Re-checking the standard convention,if the area increases,the flux into the plane increases. To oppose this,the induced current must create a field out of the plane,which is anti-clockwise. However,if the loop is stretched,the flux increases. Lenz's law states the induced current opposes the change. Thus,the correct answer is $(b)$.

$A$ circular loop of flexible conducting material is kept in a magnetic field directed perpendicularly into its plane. By holding the loop at diametrically opposite points,it is suddenly stretched outwards,then

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