A circular road runs round a circular ground. | vedclass

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(B) Let the radius of the outer circle be $R$ and the radius of the inner circle be $r$.The width of the road is the difference between the radii,whic

Vedclass · Accepted Answer

$10.5$

Vedclass · Answer

(B) Let the radius of the outer circle be $R$ and the radius of the inner circle be $r$.The width of the road is the difference between the radii,which is $(R - r)$.The circumference of the outer circle is $2 \pi R$ and the circumference of the inner circle is $2 \pi r$.Given that the difference between the circumferences is $66 \, m$:$2 \pi R - 2 \pi r = 66$$2 \pi (R - r) = 66$$2 	imes \frac{22}{7} 	imes (R - r) = 66$$(R - r) = 66 	imes \frac{7}{22} 	imes \frac{1}{2}$$(R - r) = 3 	imes 7 	imes \frac{1}{2} = \frac{21}{2} = 10.5 \, m$.Thus,the width of the road is $10.5 \, m$.

$A$ circular road runs round a circular ground. If the difference between the circumferences of the outer circle and the inner circle is $66 \, m$,the width of the road is ....... $m$.

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