A circular wire of length 168 text{ cm} is cu | vedclass

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(D) The total length of the wire is the perimeter of the rectangle,which is $168 	ext{ cm}$.Let the sides of the rectangle be $5x$ and $7x$.The perim

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$\sqrt{3626}$

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(D) The total length of the wire is the perimeter of the rectangle,which is $168 	ext{ cm}$.Let the sides of the rectangle be $5x$ and $7x$.The perimeter of a rectangle is given by $2(L + b) = 168$.$2(5x + 7x) = 168$$2(12x) = 168$$24x = 168$$x = 168 / 24 = 7$.Thus,the length $L = 5 	imes 7 = 35 	ext{ cm}$ and the breadth $b = 7 	imes 7 = 49 	ext{ cm}$.The diagonal of the rectangle is given by $\sqrt{L^2 + b^2}$.Diagonal $= \sqrt{35^2 + 49^2} = \sqrt{1225 + 2401} = \sqrt{3626} 	ext{ cm}$.

$A$ circular wire of length $168 \text{ cm}$ is cut and bent in the form of a rectangle whose sides are in the ratio of $5:7$. What is the length (in $\text{cm}$) of the diagonal of the rectangle?

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