A cistern can be filled by two pipes A and B | vedclass

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(B) The part of the tank filled by pipe $A$ in $1 	ext{ hour}$ is $\frac{1}{4}$.The part of the tank filled by pipe $B$ in $1 	ext{ hour}$ is $\frac

Vedclass · Accepted Answer

$3 \frac{3}{7} 	ext{ hrs}$

Vedclass · Answer

(B) The part of the tank filled by pipe $A$ in $1 	ext{ hour}$ is $\frac{1}{4}$.The part of the tank filled by pipe $B$ in $1 	ext{ hour}$ is $\frac{1}{6}$.The part of the tank emptied by pipe $C$ in $1 	ext{ hour}$ is $\frac{1}{8}$.When all three pipes are opened simultaneously,the net part of the tank filled in $1 	ext{ hour}$ is $\frac{1}{4} + \frac{1}{6} - \frac{1}{8}$.Taking the least common multiple $(LCM)$ of $4, 6,$ and $8$,which is $24$:Net part filled in $1 	ext{ hour} = \frac{6 + 4 - 3}{24} = \frac{7}{24}$.Therefore,the total time required to fill the cistern is the reciprocal of the net part filled per hour:$	ext{Time} = \frac{24}{7} = 3 \frac{3}{7} 	ext{ hours}$.

$A$ cistern can be filled by two pipes $A$ and $B$ in $4$ $hours$ and $6$ $hours$ respectively. When full,the tank can be emptied by a third pipe in $8$ $hours$. If all the taps are turned on at the same time,the cistern will be full in?

Similar Questions

Three pipes $A, B$ and $C$ can fill a cistern in $10$ $hours$,$12$ $hours$ and $15$ $hours$ respectively. First $A$ was opened. After $1$ $hour$,$B$ was opened and after $2$ $hours$ from the start of $A$,$C$ was also opened. Find the time in which the cistern is just full.

$A$ boy and a girl together fill a cistern with water. The boy pours $4$ litres of water every $3$ minutes and the girl pours $3$ litres every $4$ minutes. How much time (in minutes) will it take to fill $100$ litres of water in the cistern?

Two pipes $A$ and $B$ can fill a water tank in $10$ and $12$ $min,$ respectively,and a third pipe $C$ can empty it at the rate of $6$ $gallons$ per $min.$ If $A, B,$ and $C$ are opened together,they fill the tank in $20$ $min.$ What is the capacity (in $gallons$) of the tank?

$A$ tank is filled in $5$ $hours$ by three pipes $A, B$ and $C$. Pipe $C$ is twice as fast as $B,$ and $B$ is twice as fast as $A$. How much time (in $hours$) will pipe $A$ alone take to fill the tank?

Two pipes $A$ and $B$ can fill a cistern in $3$ $hours$ and $5$ $hours,$ respectively. Pipe $C$ can empty it in $2$ $hours.$ If all the three pipes are open,in how many $hours$ will the cistern be full?

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