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(C) To find the mean number of days,we first calculate the class mark $(x_i)$ for each interval using the formula: $x_i = \frac{	ext{Upper class limi

Vedclass · Accepted Answer

$12.48$

Vedclass · Answer

(C) To find the mean number of days,we first calculate the class mark $(x_i)$ for each interval using the formula: $x_i = \frac{	ext{Upper class limit} + 	ext{Lower class limit}}{2}$.Using the assumed mean method with $a = 17$,we calculate $d_i = x_i - a$ and $f_i d_i$:Number of daysNumber of students $(f_i)$$x_i$$d_i = x_i - 17$$f_i d_i$$0-6$$11$$3$$-14$$-154$$6-10$$10$$8$$-9$$-90$$10-14$$7$$12$$-5$$-35$$14-20$$4$$17$$0$$0$$20-28$$4$$24$$7$$28$$28-38$$3$$33$$16$$48$$38-40$$1$$39$$22$$22$Total$\sum f_i = 40$$\sum f_i d_i = -181$The mean $\bar{x}$ is given by $\bar{x} = a + \frac{\sum f_i d_i}{\sum f_i}$.Substituting the values: $\bar{x} = 17 + \frac{-181}{40} = 17 - 4.525 = 12.475$.Rounding to two decimal places,the mean number of days is $12.48$ days.

Lifetimes (in hours)	$0-20$	$20-40$	$40-60$	$60-80$	$80-100$	$100-120$
Frequency	$10$	$35$	$52$	$61$	$38$	$29$

Class interval	Frequency
$0-10$	$5$
$10-20$	$x$
$20-30$	$20$
$30-40$	$15$
$40-50$	$y$
$50-60$	$5$
Total	$60$

Height (in $cm$)	Number of girls
Less than $140$	$4$
Less than $145$	$11$
Less than $150$	$29$
Less than $155$	$40$
Less than $160$	$46$
Less than $165$	$51$

Number of cars	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$7$	$14$	$13$	$12$	$20$	$11$	$15$	$8$

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$2, 6, 4, 5, 0, 2, 1, 3, 2, 3$
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The following data provides information on the observed lifetimes (in $hours$) of $225$ electrical components:
Lifetimes (in hours) $0-20$ $20-40$ $40-60$ $60-80$ $80-100$ $100-120$
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If the median of the distribution given below is $28.5,$ find the values of $x$ and $y$.
Class interval Frequency
$0-10$ $5$
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$30-40$ $15$
$40-50$ $y$
$50-60$ $5$
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$A$ survey regarding the heights (in $cm$) of $51$ girls of Class $X$ of a school was conducted and the following data was obtained:Height (in $cm$)Number of girlsLess than $140$$4$Less than $145$$11$Less than $150$$29$Less than $155$$40$Less than $160$$46$Less than $165$$51$Find the median height.