A closed tank has two compartments A and B, b | vedclass

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Question

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$n _{ A }=$ No. of moles in vessel $- A =\frac{5 	imes 1}{ R 	imes 400}=\frac{1}{80 R }$    $ . . . . . (1)$

$n_B=$ No. of m

Vedclass · Accepted Answer

$2.22$

Vedclass · Answer

(image)

$n _{ A }=$ No. of moles in vessel $- A =\frac{5 	imes 1}{ R 	imes 400}=\frac{1}{80 R }$    $ . . . . . (1)$

$n_B=$ No. of moles in vessel $-B=\frac{1 	imes 3}{R 	imes 300}=\frac{1}{100 R}$  $ . . . . . (2)$

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Pressure and temperature on the both sides are must be same.

$\eta_A^{\prime}=$ No. of moles in vessel $-A=\frac{P x}{R T}$    $. . . . . (3)$

$n_B^{\prime}=$ No. of moles in vessel $-B=\frac{P(4-x)}{R T}$   $. . . . . (4)$

Using equation $1,2,3$ and 4 , we get $x=\frac{20}{9}=2.22$

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