$A$ closely wound solenoid of $800$ turns and area of cross section $2.5 \times 10^{-4} \;m^{2}$ carries a current of $3.0 \;A$. If the solenoid is free to turn about the vertical direction and a uniform horizontal magnetic field of $0.25 \;T$ is applied,what is the magnitude of torque on the solenoid when its axis makes an angle of $30^{\circ}$ with the direction of the applied field?

  • A
    $7.5 \times 10^{-2} \;N \,m$
  • B
    $2.5 \times 10^{-2} \;N \,m$
  • C
    $6.5 \times 10^{-3} \;N \,m$
  • D
    $1.25 \times 10^{-2} \;N \,m$

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