A coil has an inductance of 0.7 , H and is jo | vedclass

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(B) Given: $L = 0.7 \, H$,$R = 220 \, \Omega$,$V_{rms} = 220 \, V$,$f = 50 \, Hz$.First,calculate the inductive reactance $X_L$:$X_L = 2 \pi f L = 2 \

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$45^o, \, 0.5 \, A$

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(B) Given: $L = 0.7 \, H$,$R = 220 \, \Omega$,$V_{rms} = 220 \, V$,$f = 50 \, Hz$.First,calculate the inductive reactance $X_L$:$X_L = 2 \pi f L = 2 	imes \frac{22}{7} 	imes 50 	imes 0.7 = 220 \, \Omega$.Phase angle $\phi$ is given by:$	an \phi = \frac{X_L}{R} = \frac{220}{220} = 1 \implies \phi = 45^o$.The total impedance $Z$ is:$Z = \sqrt{R^2 + X_L^2} = \sqrt{220^2 + 220^2} = 220\sqrt{2} \, \Omega$.The $rms$ current $I_{rms}$ is:$I_{rms} = \frac{V_{rms}}{Z} = \frac{220}{220\sqrt{2}} = \frac{1}{\sqrt{2}} \, A$.The wattless component of current is $I_{rms} \sin \phi$:$I_{wattless} = I_{rms} \sin 45^o = \frac{1}{\sqrt{2}} 	imes \frac{1}{\sqrt{2}} = 0.5 \, A$.Thus,the phase angle is $45^o$ and the wattless component is $0.5 \, A$.

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