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(A) The voltage gain $(A_v)$ of a common emitter transistor amplifier is given by the formula: $A_v = \beta 	imes \frac{R_L}{R_i}$ Where $\beta$ is t

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$900$

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(A) The voltage gain $(A_v)$ of a common emitter transistor amplifier is given by the formula: $A_v = \beta 	imes \frac{R_L}{R_i}$ Where $\beta$ is the current gain,$R_L$ is the load resistance,and $R_i$ is the input resistance. Given: $\beta = 50$ $R_L = 9 \, k\Omega = 9000 \, \Omega$ $R_i = 500 \, \Omega$ Substituting the values into the formula: $A_v = 50 	imes \frac{9000}{500}$ $A_v = 50 	imes 18$ $A_v = 900$ Therefore,the voltage gain of the amplifier is $900$.

$A$ common emitter transistor amplifier has a current gain of $50$. If the load resistance is $9 \, k\Omega$ and the input resistance is $500 \, \Omega$,the voltage gain of the amplifier will be:

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