A complex compound which can show optical iso | vedclass

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(C) $1$. Optical isomerism requires the absence of a plane of symmetry or center of inversion in the complex. This is typically observed in chiral com

Vedclass · Accepted Answer

$[Cr(ox)_3]^{3-}$

Vedclass · Answer

(C) $1$. Optical isomerism requires the absence of a plane of symmetry or center of inversion in the complex. This is typically observed in chiral complexes.$2$. Geometrical isomerism is observed in complexes that can form $cis$ and $trans$ isomers.$3$. $[Co(en)_2Cl_2]^+$ shows both geometrical ($cis$ and $trans$) and optical isomerism (for the $cis$ form).$4$. $[Co(NH_3)_5Cl]^{2+}$ does not show either type of isomerism.$5$. $[Cr(ox)_3]^{3-}$ is a tris-chelated complex of the type $[M(AA)_3]$. It does not have geometrical isomers because all donor atoms are identical,but it exists as a pair of enantiomers (optical isomers).$6$. $[Pt(NH_3)_2Cl_2]$ is a square planar complex that shows geometrical isomerism ($cis$ and $trans$) but cannot show optical isomerism due to the presence of a plane of symmetry in the square planar geometry.$7$. Therefore,$[Cr(ox)_3]^{3-}$ is the correct answer.

$A$ complex compound which can show optical isomerism but not geometrical isomerism is:

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