A compound X contains 32 % of A,20 % of B,and | vedclass

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(A) $1$. Calculate the percentage of $C$: $100 \% - (32 \% + 20 \%) = 48 \%$.$2$. Determine the number of moles for each element by dividing the perce

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$ABC_3$

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(A) $1$. Calculate the percentage of $C$: $100 \% - (32 \% + 20 \%) = 48 \%$.$2$. Determine the number of moles for each element by dividing the percentage by its atomic mass:- For $A$: $32 / 64 = 0.5$- For $B$: $20 / 40 = 0.5$- For $C$: $48 / 32 = 1.5$$3$. Divide by the smallest number of moles $(0.5)$ to get the simplest ratio:- $A$: $0.5 / 0.5 = 1$- $B$: $0.5 / 0.5 = 1$- $C$: $1.5 / 0.5 = 3$$4$. The simplest whole number ratio of $A:B:C$ is $1:1:3$.Therefore,the empirical formula of compound $X$ is $ABC_3$.

$A$ compound $X$ contains $32 \%$ of $A$,$20 \%$ of $B$,and the remaining percentage of $C$. Then,the empirical formula of $X$ is:
(Given atomic masses of $A = 64$,$B = 40$,$C = 32 \ u$)

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$A$ compound $X$ contains $32 \%$ of $A$,$20 \%$ of $B$,and the remaining percentage of $C$. Then,the empirical formula of $X$ is:(Given atomic masses of $A = 64$,$B = 40$,$C = 32 \ u$)