A compound that shows positive iodoform test | vedclass

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Question

(A) Iodoform test with sodium hypoiodite is used for the detection of the $CH_3CO-$ group or the $CH_3CH(OH)-$ group,which produces the $CH_3CO-$ grou

Vedclass · Accepted Answer

$2$-pentanone

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(A) Iodoform test with sodium hypoiodite is used for the detection of the $CH_3CO-$ group or the $CH_3CH(OH)-$ group,which produces the $CH_3CO-$ group upon oxidation.Iodoform reaction with the given compounds is as follows:$(A)$ $CH_3CH_2CH_2COCH_3 + 3I_2 + 4NaOH \longrightarrow CH_3CH_2CH_2COONa + CHI_3 + 3NaI + 3H_2O$. It gives a positive iodoform test due to the presence of the $CH_3CO-$ group.$(B)$ $CH_3CH_2COCH_2CH_3$ does not contain a $CH_3CO-$ group,so it gives a negative iodoform test.$(C)$ $CH_3CH_2CH(OH)CH_2CH_3$ does not contain a $CH_3CH(OH)-$ group,so it gives a negative iodoform test.$(D)$ $CH_3CH_2CH_2CH_2CH_2OH$ is a primary alcohol that does not contain a $CH_3CH(OH)-$ group,so it gives a negative iodoform test.

$A$ compound that shows positive iodoform test is

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