$A$ conducting rod $AC$ of length $4l$ is rotated about a point $O$ in a uniform magnetic field $\vec{B}$ directed into the paper. $AO = l$ and $OC = 3l$. Then:

  • A
    $V_A - V_O = \frac{B\omega l^2}{2}$
  • B
    $V_O - V_C = \frac{7}{2}B\omega l^2$
  • C
    $V_A - V_C = 4B\omega l^2$
  • D
    $V_C - V_O = \frac{9}{2}B\omega l^2$

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