$A$ conducting rod of length $l$ is falling with a velocity $v$ perpendicular to a uniform horizontal magnetic field $B$. The potential difference between its two ends will be

  • A
    $2Blv$
  • B
    $Blv$
  • C
    $\frac{1}{2}Blv$
  • D
    ${B^2}{l^2}{v^2}$

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