$A$ conducting square frame of side $a$ and a long straight wire carrying current $I$ are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity $V$. The $emf$ induced in the frame will be proportional to

  • A
    $\frac{1}{x^2}$
  • B
    $\frac{1}{(2x - a)^2}$
  • C
    $\frac{1}{(2x + a)}$
  • D
    $\frac{1}{(2x - a)(2x + a)}$

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