A conical vessel of base radius 2 cm and hei | vedclass

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(C) The volume of the conical vessel is given by the formula $V = \frac{1}{3} \pi r^2 h$.Substituting the given values,$r = 2 \ cm$ and $h = 3 \ cm$:$

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$1$

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(C) The volume of the conical vessel is given by the formula $V = \frac{1}{3} \pi r^2 h$.Substituting the given values,$r = 2 \ cm$ and $h = 3 \ cm$:$V = \frac{1}{3} 	imes \pi 	imes (2)^2 	imes 3 = 4\pi \ cm^3$.When this liquid is transferred to a cylindrical jar of radius $R = 2 \ cm$,let the height of the kerosene level be $h_{jar}$.The volume of the liquid remains the same,so the volume in the cylinder is $V = \pi R^2 h_{jar}$.$4\pi = \pi 	imes (2)^2 	imes h_{jar}$.$4\pi = 4\pi 	imes h_{jar}$.Therefore,$h_{jar} = 1 \ cm$.

$A$ conical vessel of base radius $2 \ cm$ and height $3 \ cm$ is filled with kerosene. This liquid leaks through a hole in the bottom and collects in a cylindrical jar of radius $2 \ cm$. The kerosene level in the jar is.....$cm$

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