$A$ constant force acts on a body of mass $0.9 \,kg$ at rest for $10 \,s$. If the body moves a distance of $250 \,m$,the magnitude of the force is.........$N$

An object with mass $500 \ g$ moves along the $x$-axis with speed $v = 4 \sqrt{x} \ m/s$. The force acting on the object is ....... $N$.

$A$ particle of mass $M$ originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation $F = F_{0} \left(1 - \left(\frac{t - T}{T}\right)^{2}\right)$. Where $F_{0}$ and $T$ are constants. The force acts only for the time interval $2T$. The velocity $v$ of the particle after time $2T$ is:

$A$ body of mass $10 \,kg$ is acted upon by a force given by the equation $F = (3t^2 - 30) \,N$. The initial velocity of the body is $10 \,m/s$. What is the velocity of the body after $5 \,s$ (in $\,m/s$)?

The magnitude of the external force acting on moving bodies can be known directly by

$A$ force of $5 \, N$ acts on a body of weight $9.8 \, N$. What is the acceleration produced in $m/s^2$?