A contractor undertakes to dig a canal 12 , k | vedclass

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(B) The formula for work completion is $\frac{M_1 D_1}{W_1} = \frac{M_2 D_2}{W_2}$.Given:$M_1 = 45$ men,$D_1 = 200$ days,$W_1 = 4.5 \, km$.Remaining w

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$55$

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(B) The formula for work completion is $\frac{M_1 D_1}{W_1} = \frac{M_2 D_2}{W_2}$.Given:$M_1 = 45$ men,$D_1 = 200$ days,$W_1 = 4.5 \, km$.Remaining work $W_2 = 12 - 4.5 = 7.5 \, km$.Remaining time $D_2 = 350 - 200 = 150$ days.Let $M_2$ be the total number of men required to complete the remaining work in time.Substituting the values:$\frac{45 	imes 200}{4.5} = \frac{M_2 	imes 150}{7.5}$$M_2 = \frac{45 	imes 200 	imes 7.5}{4.5 	imes 150}$$M_2 = \frac{45 	imes 200 	imes 7.5}{675}$$M_2 = 100$ men.Extra men required $= M_2 - M_1 = 100 - 45 = 55$ men.

$A$ contractor undertakes to dig a canal $12 \, km$ long in $350 \, days$ and employs $45$ men. After $200 \, days$ he finds that only $4.5 \, km$ of the canal has been completed. Find the number of extra men he must employ to finish the work in time (in $men$).

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