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(B) For a parallel beam of light to emerge as a parallel beam from a combination of a convex and a concave lens,the second focal point of the convex l

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$15$

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(B) For a parallel beam of light to emerge as a parallel beam from a combination of a convex and a concave lens,the second focal point of the convex lens must coincide with the first focal point of the concave lens.Let $f_1 = 20 \ cm$ be the focal length of the convex lens and $f_2 = 5 \ cm$ be the focal length of the concave lens.The distance between the lenses is given by $d = f_1 - f_2$.Substituting the values,we get $d = 20 \ cm - 5 \ cm = 15 \ cm$.

$A$ convex lens $A$ of focal length $20 \ cm$ and a concave lens $B$ of focal length $5 \ cm$ are kept along the same axis with a distance $d$ between them. If a parallel beam of light falling on $A$ leaves $B$ as a parallel beam,then the distance $d$ in $cm$ will be

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