A convex mirror and a concave mirror of radiu | vedclass

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(A) For the concave mirror,the radius of curvature $R = -10\; cm$,so the focal length $f = -5\; cm$. The object is placed midway between the mirrors,s

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On the pole of the convex mirror

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(A) For the concave mirror,the radius of curvature $R = -10\; cm$,so the focal length $f = -5\; cm$. The object is placed midway between the mirrors,so the object distance $u = -7.5\; cm$.Using the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$:$\frac{1}{v} + \frac{1}{-7.5} = \frac{1}{-5}$$\frac{1}{v} = \frac{1}{7.5} - \frac{1}{5} = \frac{2}{15} - \frac{3}{15} = -\frac{1}{15}$$v = -15\; cm$.Since the mirrors are $15\; cm$ apart,this image is formed exactly at the pole of the convex mirror.For the convex mirror,the object is at its pole,so $u = 0$. The focal length $f = +5\; cm$.Using the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$:$\frac{1}{v} + \frac{1}{0} = \frac{1}{5}$This implies the light rays are incident on the pole and reflect back along the same path,meaning the final image is formed at the pole of the convex mirror.

$A$ convex mirror and a concave mirror of radius $10\; cm$ each are placed $15\; cm$ apart facing each other. An object is placed midway between them. If the reflection first takes place in the concave mirror and then in the convex mirror,the position of the final image is:

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