A copper complex crystallising in a CCP latti | vedclass

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Question

(A) For a $CCP$ lattice,the number of atoms per unit cell is $z = 4$.The formula for density is $d = \frac{z 	imes M}{N_{A} 	imes a^{3}}$.Given: $d

Vedclass · Accepted Answer

$106$

Vedclass · Answer

(A) For a $CCP$ lattice,the number of atoms per unit cell is $z = 4$.The formula for density is $d = \frac{z 	imes M}{N_{A} 	imes a^{3}}$.Given: $d = 7.62 \ g \ cm^{-3}$,$a = 0.4518 \ nm = 0.4518 	imes 10^{-7} \ cm$,$N_{A} = 6.022 	imes 10^{23} \ mol^{-1}$.Rearranging for molar mass $M$: $M = \frac{d 	imes N_{A} 	imes a^{3}}{z}$.$M = \frac{7.62 	imes 6.022 	imes 10^{23} 	imes (0.4518 	imes 10^{-7})^{3}}{4}$.$M = \frac{7.62 	imes 6.022 	imes 10^{23} 	imes 9.223 	imes 10^{-23}}{4} \approx 105.8 \ g \ mol^{-1}$.Rounding to the nearest integer,we get $106 \ g \ mol^{-1}$.

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