$A$ cycle wheel of radius $0.4\ m$ completes one revolution in one second. Then,the acceleration of a point on the rim of the cycle wheel will be:

$A$ particle is moving on a circular path of radius $r$ with uniform speed $v$. What is the displacement of the particle after it has described an angle of $60^{\circ}$?

In the case of uniform circular motion,which of the following physical quantities does not remain constant?

If $\vec{L}$ and $\vec{P}$ represent the angular momentum and linear momentum respectively of a particle of mass $m$ having position vector $\vec{r} = a(\hat{i} \cos \omega t + \hat{j} \sin \omega t)$,the direction of the force acting on the particle is:

$A$ particle $P$ is moving in a circle of radius $a$ with a uniform speed $v$. $C$ is the centre of the circle and $AB$ is a diameter. When passing through $B$,the angular velocity of $P$ about $A$ and $C$ are in the ratio:

Write the equations for centripetal acceleration and centripetal force for uniform circular motion.