A cyclist goes once around a circular track o | vedclass

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(A) The diameter of the circular track is $D = 105 \, m$. Therefore, the radius $R = \frac{105}{2} = 52.5 \, m$.The time taken to complete one round i

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$1.1$

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(A) The diameter of the circular track is $D = 105 \, m$. Therefore, the radius $R = \frac{105}{2} = 52.5 \, m$.The time taken to complete one round is $t = 5 \, minutes = 5 	imes 60 \, s = 300 \, s$.The distance covered in one round is equal to the circumference of the circle, which is $2 \pi R$.Distance $= 2 	imes 3.14 	imes 52.5 = 329.7 \, m$.Speed $= \frac{	ext{Distance}}{	ext{Time}} = \frac{329.7}{300} = 1.099 \, m/s \approx 1.1 \, m/s$.

$A$ cyclist goes once around a circular track of diameter $105 \, m$ in $5 \, minutes$. Calculate his speed. (in $m/s$)

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