A cylindrical vessel of height 5, cm and radi | vedclass

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Question

(A) Volume of the cylindrical vessel $=$ Volume of the cone$\pi r_{1}^{2} h_{1} = \frac{1}{3} \pi r_{2}^{2} h_{2}$Here,for the cylinder,$r_{1} = 4\, c

Vedclass · Accepted Answer

$6.67$

Vedclass · Answer

(A) Volume of the cylindrical vessel $=$ Volume of the cone$\pi r_{1}^{2} h_{1} = \frac{1}{3} \pi r_{2}^{2} h_{2}$Here,for the cylinder,$r_{1} = 4\, cm$ and $h_{1} = 5\, cm$.For the cone,$r_{2} = 6\, cm$ and we need to find $h_{2}$.Substituting the values into the formula:$\pi 	imes (4)^2 	imes 5 = \frac{1}{3} 	imes \pi 	imes (6)^2 	imes h_{2}$$16 	imes 5 = \frac{1}{3} 	imes 36 	imes h_{2}$$80 = 12 	imes h_{2}$$h_{2} = \frac{80}{12} = \frac{20}{3} = 6.67\, cm$.

$A$ cylindrical vessel of height $5\, cm$ and radius $4\, cm$ is completely filled with sand. When this sand is poured out,it forms a right circular cone of radius $6\, cm$. What will be the height of this cone? (in $cm$)

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