A dealer buys a table listed at Rs. 1,500 and | vedclass

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(A) The single equivalent discount for successive discounts of $20 \%$ and $10 \%$ is calculated as:$D_{eq} = \left(20 + 10 - \frac{20 	imes 10}{100}

Vedclass · Accepted Answer

$1320$

Vedclass · Answer

(A) The single equivalent discount for successive discounts of $20 \%$ and $10 \%$ is calculated as:$D_{eq} = \left(20 + 10 - \frac{20 	imes 10}{100}ight) \% = (30 - 2) \% = 28 \%$.The cost price $(C.P.)$ of the table after discounts is:$C.P. = 1500 	imes \left(1 - \frac{28}{100}ight) = 1500 	imes 0.72 = Rs. 1080$.Including the transportation cost,the total cost price $(C.P._{total})$ is:$C.P._{total} = 1080 + 20 = Rs. 1100$.To earn a profit of $20 \%$,the selling price $(S.P.)$ is:$S.P. = C.P._{total} 	imes \left(1 + \frac{20}{100}ight) = 1100 	imes 1.2 = Rs. 1320$.

$A$ dealer buys a table listed at $Rs. 1,500$ and gets successive discounts of $20 \%$ and $10 \%$. He spends $Rs. 20$ on transportation and sells it at a profit of $20 \%$. Find the selling price of the table (in $Rs.$).

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