A diatomic gas,having C_{p} = frac{7}{2} R an | vedclass

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Question

(B) For an ideal gas,the change in internal energy is given by $dU = n C_{v} dT$.The heat supplied at constant pressure is given by $dQ = n C_{p} dT$.

Vedclass · Accepted Answer

$5: 7: 2$

Vedclass · Answer

(B) For an ideal gas,the change in internal energy is given by $dU = n C_{v} dT$.The heat supplied at constant pressure is given by $dQ = n C_{p} dT$.The work done in an isobaric process is given by $dW = P dV = n R dT$.Therefore,the ratio $dU : dQ : dW$ is $n C_{v} dT : n C_{p} dT : n R dT$,which simplifies to $C_{v} : C_{p} : R$.Substituting the given values,we get $\frac{5}{2} R : \frac{7}{2} R : R$.Multiplying by $\frac{2}{R}$,we obtain the ratio $5 : 7 : 2$.

$A$ diatomic gas,having $C_{p} = \frac{7}{2} R$ and $C_{v} = \frac{5}{2} R$,is heated at constant pressure. The ratio $dU : dQ : dW$ is:

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