A diatomic molecule has a dipole moment of 1. | vedclass

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(D) The dipole moment $(\mu)$ is given by the formula $\mu = q 	imes d$,where $q$ is the charge and $d$ is the bond length.Given: $\mu = 1.2 \, D = 1

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) The dipole moment $(\mu)$ is given by the formula $\mu = q 	imes d$,where $q$ is the charge and $d$ is the bond length.Given: $\mu = 1.2 \, D = 1.2 	imes 10^{-18} \, esu \cdot cm$ and $d = 10^{-10} \, m = 10^{-8} \, cm$.Substituting the values: $1.2 	imes 10^{-18} = q 	imes 10^{-8}$.Solving for $q$: $q = \frac{1.2 	imes 10^{-18}}{10^{-8}} = 1.2 	imes 10^{-10} \, esu$.The electronic charge $e$ is approximately $4.8 	imes 10^{-10} \, esu$.The fraction of electronic charge is $\frac{q}{e} 	imes 100 = \frac{1.2 	imes 10^{-10}}{4.8 	imes 10^{-10}} 	imes 100 = 0.25 	imes 100 = 25 \%$.Thus,the correct option is $D$.

$A$ diatomic molecule has a dipole moment of $1.2 \, D$. If its bond length is equal to $10^{-10} \, m$,then the fraction of an electronic charge on each atom will be .............. $\%$

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