$A$ diffraction pattern is obtained using a beam of red light. If the red light is replaced by blue light,then:

$A$ Fraunhofer diffraction pattern due to a single slit of width $0.3 \text{ mm}$ is obtained on a screen placed at a distance of $3 \text{ m}$ from the slit. The first minima lie at $5.5 \text{ mm}$ on either side of the central maximum on the screen. The wavelength of light used is (in $\text{ Å}$)

"The person standing behind the open door inside the room can hear the voice of the person standing on the other side of the door but they cannot see each other". Give an experiment based on the diffraction for this statement.

In a single slit diffraction experiment,the width of the slit is made double its original width. Then the central maximum of the diffraction pattern will become

Two wavelengths of sodium light $590 \,nm$ and $596 \,nm$ are used one after another to study diffraction due to a single slit of aperture $2 \times 10^{-6} \,m$. The distance between the slit and the screen is $1.5 \,m$. The separation between the positions of the first maximum of the diffraction pattern obtained in the two cases is: (in $\,mm$)

In a Fraunhofer diffraction due to a single slit,the diffraction pattern is formed on the focal plane of a lens of focal length $f = 1 \ m$. The width of the slit is $a = 0.3 \ mm$. If the third minimum is formed at a distance of $5 \ mm$ from the central maximum,find the wavelength of light in $\mathring{A}$.