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(A) The radius of curvature of the cylindrical mirror is $R = 10 \,cm$.The focal length $f$ of the mirror is given by $f = \frac{R}{2} = \frac{10 \,cm

Vedclass · Accepted Answer

$2$

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(A) The radius of curvature of the cylindrical mirror is $R = 10 \,cm$.The focal length $f$ of the mirror is given by $f = \frac{R}{2} = \frac{10 \,cm}{2} = 5 \,cm$.The field of view $	heta$ (in radians) for an observer at a large distance is determined by the arc length $s$ and the focal length $f$ as $	heta = \frac{s}{f}$.Given the arc length $s = 10 \,cm$ and $f = 5 \,cm$,we have:$	heta = \frac{10 \,cm}{5 \,cm} = 2 \,rad$.Thus,the correct option is $A$.

$A$ driving mirror consists of a cylindrical mirror of radius of curvature $10 \,cm$ and the length over the curved surface is $10 \,cm$. If the eye of the driver is assumed to be at a great distance from the mirror,then the field of view in radians is: (in $.0$)

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