Dry air is passed through a solution containi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the Ostwald-Walker method,the relative lowering of vapour pressure is given by the ratio of the loss in weight of the solvent to the

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(C) According to the Ostwald-Walker method,the relative lowering of vapour pressure is given by the ratio of the loss in weight of the solvent to the loss in weight of the solution.$\frac{P^0 - P_s}{P^0} = \frac{	ext{Loss in weight of solvent}}{	ext{Loss in weight of solution}} = \frac{0.05}{2.5}$Also,by Raoult's Law,$\frac{P^0 - P_s}{P^0} = \frac{n}{n + N} \approx \frac{n}{N} = \frac{w 	imes M}{m 	imes W}$Where $w = 10 \ g$ (solute),$W = 90 \ g$ (solvent),$M = 18 \ g/mol$ (molar mass of water),and $m$ is the molar mass of the solute.$\frac{0.05}{2.5} = \frac{10 	imes 18}{m 	imes 90}$$\frac{1}{50} = \frac{180}{90m} = \frac{2}{m}$$m = 2 	imes 50 = 100 \ g/mol$.

Dry air is passed through a solution containing $10 \ g$ of solute and $90 \ g$ of water,and then it is passed through pure water. The loss in weight of the solution is $2.5 \ g$ and the loss in weight of the pure solvent is $0.05 \ g$. Calculate the molecular weight of the solute.

Similar Questions

For the hyperbola $\frac{x^2}{\cos^2 \alpha} - \frac{y^2}{\sin^2 \alpha} = 1$,which of the following remains constant if $\alpha$ varies?

Which oxide of nitrogen is obtained when ammonium nitrate is heated at $250\,^oC$?

If $(-2, 6)$ is the image of the point $(4, 2)$ with respect to line $L = 0$,then $L =$

Which of the following statements is true for transition elements?

In the following common emitter circuit,if $\beta = 100$,$V_{CE} = 7\,V$,$V_{BE} = 0$,and $R_C = 2\,k\Omega$,then find the value of $I_B$ in $mA$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module