A factory manufactures 120000 pencils daily. | vedclass

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Question

(C) The curved surface area of a cylinder is given by $CSA = 2 \pi r h$,where $2 \pi r$ is the circumference of the base and $h$ is the length (height

Vedclass · Accepted Answer

$2250$

Vedclass · Answer

(C) The curved surface area of a cylinder is given by $CSA = 2 \pi r h$,where $2 \pi r$ is the circumference of the base and $h$ is the length (height).Given,circumference of the base $= 1.5 \,cm$ and length $h = 25 \,cm$.Curved surface area of one pencil $= 1.5 \,cm 	imes 25 \,cm = 37.5 \,cm^2$.Since $1 \,dm = 10 \,cm$,then $1 \,dm^2 = 100 \,cm^2$. Therefore,$1 \,cm^2 = 0.01 \,dm^2$.Curved surface area of one pencil in $dm^2 = 37.5 	imes 0.01 = 0.375 \,dm^2$.Total curved surface area for $120000$ pencils $= 120000 	imes 0.375 \,dm^2 = 45000 \,dm^2$.Cost of colouring $= 45000 \,dm^2 	imes \operatorname{Rs.} 0.05/dm^2 = \operatorname{Rs.} 2250$.

Part $I$	Part $II$
$1.$ $CSA$ of a cylinder	$a.$ $3\pi r^2$
$2.$ $CSA$ of a sphere	$b.$ $2\pi rh$
$3.$ $CSA$ of a cone	$c.$ $4\pi r^2$
$4.$ $TSA$ of a hemisphere	$d.$ $\pi rl$

$A$ factory manufactures $120000$ pencils daily. The pencils are cylindrical in shape,each of length $25 \,cm$ and circumference of base $1.5 \,cm$. Determine the cost of colouring the curved surfaces of the pencils manufactured in one day at $\operatorname{Rs.} 0.05$ per $dm^2$ (in $Rs.$).

Similar Questions

Which of the following correctly matches the information given in Part $I$ and Part $II$?

Part $I$ Part $II$

$1.$ $CSA$ of a cylinder $a.$ $3\pi r^2$

$2.$ $CSA$ of a sphere $b.$ $2\pi rh$

$3.$ $CSA$ of a cone $c.$ $4\pi r^2$

$4.$ $TSA$ of a hemisphere $d.$ $\pi rl$

$A$ building is in the form of a cylinder surmounted by a hemispherical vaulted dome and contains $41 \frac{19}{21} \, m^3$ of air. If the internal diameter of the dome is equal to its total height above the floor,find the height of the building? (in $m$)

The volume of a cylinder is $20 \pi \, cm^3$ and its height is $5 \, cm$. Then,the diameter of the cylinder is $\ldots \ldots \ldots \ldots \, cm$.

The base of a cone with radius $15 \, cm$ and height $20 \, cm$ is hemispherical. Find the total surface area of this article. $(\pi = 3.14)$ (in $cm^2$) (in $.5$)

The diameters of a frustum of a cone are $32 \,cm$ and $20 \,cm$. If its height is $8 \,cm$,find its curved surface area and volume. $(\pi = 3.14)$

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