A fan is making 600 revolutions per minute. I | vedclass

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(B) The angular velocity $\omega$ is given by $\omega = 2\pi n$,where $n$ is the frequency in revolutions per second.Initial frequency $n_1 = 600 	ex

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$20\,\pi 	ext{ rad/s}$

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(B) The angular velocity $\omega$ is given by $\omega = 2\pi n$,where $n$ is the frequency in revolutions per second.Initial frequency $n_1 = 600 	ext{ rpm} = \frac{600}{60} 	ext{ rev/s} = 10 	ext{ rev/s}$.Final frequency $n_2 = 1200 	ext{ rpm} = \frac{1200}{60} 	ext{ rev/s} = 20 	ext{ rev/s}$.Initial angular velocity $\omega_1 = 2\pi n_1 = 2\pi(10) = 20\pi 	ext{ rad/s}$.Final angular velocity $\omega_2 = 2\pi n_2 = 2\pi(20) = 40\pi 	ext{ rad/s}$.The increase in angular velocity is $\Delta\omega = \omega_2 - \omega_1 = 40\pi - 20\pi = 20\pi 	ext{ rad/s}$.

$A$ fan is making $600$ revolutions per minute. If after some time it makes $1200$ revolutions per minute,then the increase in its angular velocity is

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