A farmer travelled a distance of 61 , km in 9 | vedclass

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(C) Let the distance travelled on foot be $x \, km$.Then the distance travelled by bicycle is $(61 - x) \, km$.We know that $	ext{Time} = \frac{	ext

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(C) Let the distance travelled on foot be $x \, km$.Then the distance travelled by bicycle is $(61 - x) \, km$.We know that $	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}}$.Time taken on foot = $\frac{x}{4} \, hours$.Time taken on bicycle = $\frac{61 - x}{9} \, hours$.Total time taken is $9 \, hours$,so:$\frac{x}{4} + \frac{61 - x}{9} = 9$Multiply the entire equation by $36$ (the $LCM$ of $4$ and $9$):$9x + 4(61 - x) = 9 	imes 36$$9x + 244 - 4x = 324$$5x = 324 - 244$$5x = 80$$x = \frac{80}{5} = 16 \, km$.Thus,the distance travelled on foot is $16 \, km$.

$A$ farmer travelled a distance of $61 \, km$ in $9 \, hours$. He travelled partly on foot at $4 \, km/h$ and partly on bicycle at $9 \, km/h$. The distance travelled on foot is (in $km$)

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