$A$ father is now $3$ times as old as his son. $5$ years back,he was $4$ times as old as his son. The age of the son is:

The ages of $A$ and $B$ are in the ratio $6: 5$ and the sum of their ages is $44 \text{ years}$. The ratio of their ages after $8 \text{ years}$ will be:

If the present age of $X$ is half that of $Y$ and after $20$ years the age of $Y$ will be $1 \frac{1}{2}$ times that of $X$,what is the present age of $X$?

In a family,a couple has a son and a daughter. The age of the father is three times that of his daughter and the age of the son is half of his mother. The wife is $9$ years younger than her husband and the brother is $7$ years older than his sister. What is the age of the mother? (in years)

One $year$ ago,a father was four times as old as his son. In $6$ $years$ time,his age will exceed twice his son's age by $9$ $years$. The ratio of their present ages is:

Six years ago,the ratio of the ages of Kunal and Sagar was $6:5$. Four years hence,the ratio of their ages will be $11:10$. What is Sagar's age at present? (in years)