(C) Volume of the earth taken out $= (7.5 \times 6 \times 0.8) \, m^3 = 36 \, m^3$.Area of the remaining field $= (18 \times 15) - (7.5 \times 6) \, m

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(C) Volume of the earth taken out $= (7.5 \times 6 \times 0.8) \, m^3 = 36 \, m^3$.Area of the remaining field $= (18 \times 15) - (7.5 \times 6) \, m^2 = 270 - 45 = 225 \, m^2$.Let the rise in the level of the field be $h$ meters.Since the volume of the earth taken out is spread over the remaining area,we have:$225 \times h = 36$.$h = \frac{36}{225} \, m = 0.16 \, m$.Converting to centimeters: $0.16 \times 100 = 16 \, cm$.

Competitive Quantitative Aptitude Mensuration Measurement of Volume and Surface Area

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$A$ field is in the form of a rectangle of length $18\, m$ and width $15\, m$. $A$ pit,$7.5\, m$ long,$6\, m$ broad and $0.8\, m$ deep,is dug in a corner of the field and the earth taken out is evenly spread over the remaining area of the field. The level of the field raised is......$cm$

A
$12$
B
$14$
C
$16$
D
$18$

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Measurement of Volume and Surface Area

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Medium

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$A$ field is in the form of a rectangle of length $18\, m$ and width $15\, m$. $A$ pit,$7.5\, m$ long,$6\, m$ broad and $0.8\, m$ deep,is dug in a corner of the field and the earth taken out is evenly spread over the remaining area of the field. The level of the field raised is......$cm$

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$A$ monument has $50$ cylindrical pillars each of diameter $50\, cm$ and height $4\, m.$ What will be the labour charges for cleaning these pillars at the rate of $50$ $paise$ per $m^{2}?$ (in $Rs.$) (Use $\pi=3.14$)

The radius and height of a right circular cone are in the ratio $5:12$. If its volume is $314 \frac{3}{7} \text{ m}^3$,find the radius of the cone (in $\text{m}$).

The perimeter of one face of a cube is $20\, cm$. Its volume is.........$cm^3$

$A$ cylindrical vessel of radius $4 \, cm$ contains water. $A$ solid sphere of radius $3 \, cm$ is lowered into the water until it is completely immersed. The water level in the vessel will rise by (in $cm$)

$2$ cans have the same height equal to $21\, cm$. One can is cylindrical,the diameter of whose base is $10\, cm$. The other can has a square base of side $10\, cm$. What is the difference between their capacities? (in $cm^3$)

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