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(C) The formula for the extension $x$ (or $l$) in a wire is given by $x = \frac{FL}{AY}$,where $F$ is the force,$L$ is the length,$A$ is the cross-sec

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$L^2$

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(C) The formula for the extension $x$ (or $l$) in a wire is given by $x = \frac{FL}{AY}$,where $F$ is the force,$L$ is the length,$A$ is the cross-sectional area,and $Y$ is Young's modulus.Since the volume $V$ of the wire is fixed,we have $V = A 	imes L$,which implies $A = V/L$.Substituting $A$ into the extension formula: $x = \frac{FL}{(V/L)Y} = \frac{FL^2}{VY}$.Since $F$,$V$,and $Y$ are constants,the extension $x$ is proportional to $L^2$.

$A$ fixed volume of iron is drawn into a wire of length $L$. The extension $x$ produced in this wire by a constant force $F$ is proportional to

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