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(D) The number of electrons flowing per unit time is given by $\frac{n}{t} = 10^{7} \; s^{-1}$.The electric current $I$ is defined as the rate of flow

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$1.6 	imes 10^{-12} \; A$

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(D) The number of electrons flowing per unit time is given by $\frac{n}{t} = 10^{7} \; s^{-1}$.The electric current $I$ is defined as the rate of flow of charge,$I = \frac{q}{t}$.Since $q = ne$,where $e$ is the elementary charge $(e = 1.6 	imes 10^{-19} \; C)$,we have $I = \frac{ne}{t} = \left(\frac{n}{t}ight) 	imes e$.Substituting the given values: $I = 10^{7} 	imes (1.6 	imes 10^{-19} \; C) = 1.6 	imes 10^{-12} \; A$.

$A$ flow of $10^{7}$ electrons per second in a conducting wire constitutes a current of

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