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(C) The rotational kinetic energy $(K)$ of a body rotating about a fixed axis is given by the formula: $K = \frac{1}{2} I \omega^2$,where $I$ is the m

Vedclass · Accepted Answer

$0.8$

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(C) The rotational kinetic energy $(K)$ of a body rotating about a fixed axis is given by the formula: $K = \frac{1}{2} I \omega^2$,where $I$ is the moment of inertia and $\omega$ is the angular speed.Given:Kinetic energy $(K)$ = $360 \ J$Angular speed $(\omega)$ = $30 \ rad/s$Substituting the values into the formula:$360 = \frac{1}{2} 	imes I 	imes (30)^2$$360 = \frac{1}{2} 	imes I 	imes 900$$360 = 450 	imes I$$I = \frac{360}{450}$$I = 0.8 \ kg \ m^2$Therefore,the moment of inertia of the wheel is $0.8 \ kg \ m^2$.

$A$ flywheel rotating about a fixed axis has a kinetic energy of $360 \ J$ when its angular speed is $30 \ rad/s$. The moment of inertia of the wheel about the axis of rotation is ...... $kg \ m^2$.

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